# Linear Equations

## Extra Questions

Question 1: Solve 5x + 3 = 13

Solution: First method

We have 5x + 3 = 13
By subtracting 3 in both side we get
⇒ 5x + 3 – 3 = 13 – 3
⇒ 5x + 0 = 10
⇒ 5x = 10
On dividing both side by 5 we get

(5x)/(5)=(10)/(5)

Or, x=2

Second method:

We have 5x + 3 = 13
On transposing 3 to right hand side of equation we get
⇒ 5x = 13 – 3
⇒ 5x = 10
On dividing both side by 5 we get

(5x)/(5)=(10)/(5)

Or, x=2

Question 2: Solve 10 m – 5 = 35

Solution:
We have 10 m – 5 = 35
On transposing – 5 to right hand side we get
⇒ 10 m = 35 + 5
⇒ 10 m = 40
On dividing both side by 10 we get

(10 m)/(10)=(40)/(10)

Or, m=4

Question 3: Solve 4a – 30 = 10

Solution:
We have 4a – 30 = 10
On transposing – 30 to RHS we get
⇒ 4a = 10 + 30
⇒ 4a = 40
On dividing both side by 4 we get

(4 a)/(4)=(40)/(4)

Or, a=10

Question 4: Solve 40 a + 10 = 20

Solution:
We have 40 a + 10 = 20
On transposing 10 to RHS we get
⇒ 40a = 20 – 10
⇒ 40a = 10
On dividing both side by 40 we get

(40a)/(40)=(10)/(40)

Or, a=1/4

Question 5: Solve 15 m + 30 = 20 – 5

Solution:
We have 15 m + 30 = 20 – 5
⇒ 15 m + 30 = – 15
On transposing 30 to RHS we get
⇒ 15 m = – 15 – 30
⇒ 15 m = – 45
On dividing both side by 15 we get

(15m)/(15)=(-45)/(15)

Or, m=-3

Question 6: Solve 45 x + 30 = 120

Solution:
We have 45 x + 30 = 120
On transposing 30 to RHS we get
⇒ 45 x = 120 – 30
⇒ 45 x = 90
On dividing both side by 45 we get

(45x)/(45)=(90)/(2)

Or, x=2

Question 7: Sovle 50 + 25 m = 500

Solution:
We have 50 + 25 m = 500
On transposing 50 to RHS we get
⇒ 25 m = 500 – 50
⇒ 25 m = 450
On dividing both side by 25 we get

(25m)/(25)=(450)/(25)

Or, m=18

Question 8: Solve 65 = 4 b + 5

Solution:
We have 65 = 4 b + 5
On transposing 5 to LHS we get
⇒ 65 – 5 = 4 b
⇒ 60 = 4 b
On dividing both side by 4 we get

(60)/(4)=(4b)/(4)

Or, b=4