Quadrilaterals

Extra Questions Part 4

Question 6: Find the angle x

Class 8 math Quadrilaterals additional question16

Answer: We know that angle sum of a quadrilateral = 360⁰
So, `95° + 115°+ x + x = 360°`
Or, `210° + 2x = 360°`
Or, `2x = 360°- 210° = 150°`
Or, `x = 150°÷2 = 75°`


Question 7: Find the angle x

Class 8 math Quadrilaterals additional question17

Answer: We know that angle sum of a quadrilateral = 360⁰
So, `120°+ x + x + x = 360°`
Or, `120°+ 3x = 360°`
Or, `3x = 360°- 120° = 240°`
Or, `x = 240°÷3 = 80°`


Question 8: Find the angle x

Class 8 math Quadrilaterals additional question18

Answer: We know that angle sum of a quadrilateral = 360⁰
So, `84°+ x + x + x = 360°`
Or, `84°+ 3x = 360°`
Or, `3x = 360°- 84° = 276°`
Or, `x = 276°÷3 = 92°`

Question 9: Find the angle x

Class 8 math Quadrilaterals additional question19

Answer: We know that angle sum of a quadrilateral = 360⁰
So, `90°+ x + x + x = 360°`
Or, `90°+ 3x = 360°`
Or, `3x = 360°- 90° = 270°`
Or, `x = 270°÷3 = 90°`

Question 10: Find the angle x

Class 8 math Quadrilaterals additional question20

Answer: We know that angle sum of a quadrilateral = 360⁰
Or, `4x = 360°`
Or, `x = 360°÷4 = 90°`



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