Question 1: Is it possible to have a triangle with the following sides?
Answer: Making a triangle is possible only with sides given in option ‘b’. In other options, sum of two sides is either equal to or less than the third side.
Question 2: Take any point O in the interior of a triangle PQR. Is
Answer: The answer is yes in each case, because sum of any two sides of a triangle is always greater than the third side.
Question 3: AM is a median of a triangle ABC. Is AB + BC + CA > 2AM? (Consider the sides of ΔABM and ΔAMC)
Answer: In ΔABM; AB + BM > AM
Similarly, in ΔAMC; AC + CM > AM
Adding above equations, we get;
AB + BM + CM + AC > 2AM
Or, AB + BC + CA > 2AM
Question 4: ABCD is a quadrilateral. Is AB + BC + CD + DA > AC + BD?
Answer: In ΔABC; AB + BC > AC
In ΔDAC; DA + CD > AC
In ΔDAB; DA + AB > DB
In ΔDCB; CD + CB > DB
Adding above equations, we get;
2AB + 2BC + 2 CD + 2AD > 2AC + 2BD
Or, 2(AB + BC + CD + AD) > 2(AC + BD)
Or, AB + BC + CD + AD > AC + BD
Question 5: ABCD is a quadrilateral. Is AB + BC + CD + DA < 2(AC + BD)?
Answer: Let us assume a point O at the point of intersection of diagonals AC and BD.
In ΔOAB; OA + OB > AB
In Δ OBC; OB + OC > BC
In ΔODC; OD + OC > CD
In ΔOAD; OD + OA > AD
Adding above equations, we get;
AB + BC + CD + DA < OA + OB + OB + OC + OC + OD + OD + OA
Or, AB + BC + CD + DA < OA + OA + OC + OC + OD + OD + OB + OB
Or, AB + BC + CD + DA < 2(OA + OC + OD + OB)
Or, AB + BC + CD + DA < 2(AC + BD)
Question 6: The lengths of two sides of a triangle are 12 cm and 15 cm. Between what two measures should the length of the third side fall?
Answer: Sum of given two sides = 12 cm + 15 cm = 27 cm
Hence, the third side should always be less than 27 cm.
The difference between given sides = 15 cm – 12 cm = 3 cm
If the third side will be = 3 cm then 12 + 3 = 15 cm shall be equal to one of the given sides.
Hence, the third side should be more than 3 cm
So, range of measure of third side = 4 cm to 26 cm.
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