# Perimeter and Area

#### Triangles as Parts of Rectangles

Let two rectangles which are shown here: Here A is a rectangle, and diagonal is cutting this rectangle in two equal halves. Both the triangles are congruent. Hence their area will be equal.

Therefore,

Area of rectangle = Area of one triangle + Area of another triangle
⇒Area of rectangle = 2 xx Area of one triangle (As both the triangles are equal)

2 xx 1/2 xx length xx breadth
= length xx breadth

Similarly, For figure B, which is a square and diagonals cut that in four equal triangles. Means all triangles are congruent.

Area of square = 2 xx Area of triangle
= 2 xx 1/2 xx Side2
= Side2

##### Generalising for other Congruent Parts of Rectangles

Let us consider the rectangle given in the figure. In this a Line EF is dividing the rectangle in two equal part. Both parts are congruent. Hence, area of one part = area of other part.
Hence, area of each congruent part = Area of rectangle ÷ 2

### In text solution based on Area(NCERT)

Question 1: Each of the following rectangles of length 6 cm and breadth 4 cm is composed of congruent polygons. Find the area of each polygon. Solution: Figure A has 6 congruent polygons.

Hence, area of each polygon = Area of rectangle ÷ 6
Area of rectangle = length X breadth
= 6 xx 4 = 24 sq cm

Hence, area of each polygon of A = 24 ÷ 6 = 4 cm2

Figure B has 4 congruent polygons.

Hence, area of each polygon = Area of rectangle ÷ 4
= 24 ÷ 4 = 6 sq cm

Figure C has 2 congruent polygons.

Hence, are of each polygon = Area of rectangle ÷ 2
= 24 ÷ 2 = 12 sq cm

Figure D has 2 congruent polygons.

Hence, are of each polygon = Area of rectangle ÷ 2
= 24 ÷ 2 = 12 sq cm

Figure E has 8 congruent polygons.

Hence, area of each polygon = Area of rectangle ÷ 8
= 24 ÷ 8 = 3 sq cm

### AREA OF A PARALLELOGRAM

A polygon is said to be a parallelogram when their opposite sides are parallel. Here; let ABCD is a parallelogram. In this AB is parallel to CD and AC is parallel to BD. One side BD of this parallelogram is extended and a perpendicular CE is drawn on it.

Here CE is called the Height of the parallelogram.

Hence;
Area of parallelogram ABCD = base x height
⇒ Area of a parallelogram = base x height.

Question 2: Find the area of following parallelograms: (i) Given, Base = 8cm, Height = 3.5 cm

Therefore, Area = Base x Height
= 8 xx 3.5c = 28.0 cm2

(ii) Given, Base = 8cm, Height = 2.5 cm

Therefore, Area = Base xx Height
= 8xx 2.5= 20.0 cm2

(iii) In a parallelogram ABCD, AB = 7.2cm and the perpendicular from C on AB is 4.5cm. Area of parallelogram ABCD = Base xx Height

= 7.2 xx 4.5 = 32.40 cm2