Question 1: The angles of quadrilateral are in the ratio 3 : 5 : 9 : 13. Find all the angles of the quadrilateral.
Answer: As you know angle sum of a quadrilateral = 360°
So, `3x + 5x + 9x + 13x = 360°`
Or, `30x = 360°`
Or, `x = 12°`
Hence, `3x = 36°`, `5x = 60°`, `9x = 108°` and `13x = 156°`
Question 2: If the diagonals of a parallelogram are equal, then show that it is a rectangle.
Answer; In the following parallelogram both diagonals are equal:
So, ΔABC ≅ ΔADC ≅ ΔABD ≅ ΔBCD
As all are right angles so the parallelogram is a rectangle.
Question 3: Show that if the diagonals of a quadrilateral bisect each other at right angles, then it is a rhombus.
Answer; In the given quadrilateral ABCD diagonals AC and BD bisect each other at right angle. We have to prove that `AB=BC=CD=AD`
In ΔAOB and ΔAOD
`DO=OB` (O is the midpoint)
`AO=AO` (common side)
`∠AOB=∠AOD` (right angle)
So, `ΔAOB≅ ΔAOD`
Similarly `AB=BC=CD=AD` can be proved which means that ABCD is a rhombus.
Question 4: Show that the diagonals of a square are equal and bisect each other at right angles.
Answer: In the figure given above let us assume that
`DO=AO` (Sides opposite equal angles are equal)
Similarly `AO=OB=OC` can be proved
This gives the proof of diagonals of square being equal.
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