Class 10 Mathematics

# Geometry Construction

## Exercise 11.2 (NCERT)

Question 1: Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct the pair of tangents to the circle and measure their lengths.

Solution: Draw a circle with radius 6 cm and centre O.

• Draw a line segment OP = 10 cm
• Make perpendicular bisector of OP which intersects OP at point O’.
• Take O’P as radius and draw another circle.
• From point P, draw tangents to points of intersection between the two circles.
• PQ = PR = 8 cm.

Justification: Radius, tangent and distance between centre and external point (from which tangent is drawn) make a right triangle. Using Pythagoras theorem, we have;

PQ^2 = OP^2 – OQ^2

= 10^2 – 6^2

= 100 – 36 = 64

Or, PQ = 8  cm

Question 2: Construct a tangent to a circle of radius 4 cm from a point on the concentric circle of radius 6 cm and measure its length. Also verify the measurement by actual calculation.

Solution: Draw two concentric circles with radii 4 cm and 6 cm.

• Draw the radius OP of bigger circle.
• Make a perpendicular bisector of OP which intersects OP at point O’.
• Taking O’P as radius, draw another circle.
• From point P, draw tangents PQ and PR; as shown in figure.

Justification: Using Pythagoras theorem, we have;

PQ^2 = OP^2 – OQ^2

= 6^2 – 4^2

= 36 – 16 = 20

Or, PQ = 2sqrt5  cm

Question 3: Draw a circle of radius 3 cm. Take two points P and Q on one of its extended diameter each at a distance of 7 cm from its centre. Draw tangents to the circle from these two points P and Q.

Solution: Draw a circle with radius 3 cm.

• Extend the diameter to A and B on either side.
• Draw perpendicular bisectors of OA and OB.
• Perpendicular bisector of OA intersects it at point O’.
• Perpendicular bisector of OB intersects it at point O”.
• Taking O’A as radius, draw the second circle.
• Taking O”B as radius, draw the third circle.
• From point A, draw tangents AP and AQ.
• From point B, draw tangents BR and BS.

Question 4: Draw a pair of tangents to a circle of radius 5 cm which are inclined to each other at an angle of 60o.

Solution: Draw a circle with radius 5 cm.

• Draw a line AP perpendicular to radius OA.
• Draw OB at 120o from OA. (Because angle at centre is double the angle between two tangents).
• Join A and B to P; to get two tangents.
• Here, ∠APB = 60o

Question 5: Draw a line segment AB of length 8 cm. Taking A as centre, draw a circle of radius 4 cm and taking B as centre, draw another circle of radius 3 cm. Construct tangents to each circle from the centre of the other circle.

Solution: Draw a line segment, AB = 8 cm.

• Taking A as centre, draw a circle with radius 4 cm.
• Taking B as centre, draw another circle with radius 3 cm.
• Draw perpendicular bisector of AB.
• Taking midpoint of AB as centre and AB as diameter, draw the third circle.
• From point A, draw tangents AR and AS.
• From point B, draw tangents BP and BQ.

Question 6: Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and ∠B = 90o. BD is the perpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangent from A to this circle.

Solution: Draw a line segment AB = 6 cm.

• Make a right angle at point B and draw BC = 8 cm.
• Draw a perpendicular BD to AC.
• We know that in a right triangle, hypotenuse is the diameter of circumcircle.
• Taking BC as diameter, draw a circle which passes through points B, C and D.
• Join A to O and taking AO as diameter, draw second circle.
• From point A, draw tangents AB and AP.

Question 7: Draw a circle with the help of a bangle. Take a point outside the circle. Construct the pair of tangents from this point to the circle.

Solution: This question can be solved as the first question.

Exercise 11.1

Exercise 11.2